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∀n ∈ ℕ, prove (21n + 4) / (14n + 3) is irreducible. Proof: gcd(21n + 4, 14n + 3) = gcd(2(21n + 4), 3(14n + 3)) = gcd(42n + 8, 42n + 9) = gcd(42n + 8, 1) = 1 ∴ (21n + 4) / (14n + 3) is irreducible. QED View quoted note →

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Nearly caught up. A pity I didn't see the Podcast sooner! Don't forget my latest boost I just did for ep7.
Ape Mithrandir's avatar Ape Mithrandir
∀n ∈ ℕ, prove (21n + 4) / (14n + 3) is irreducible. Proof: gcd(21n + 4, 14n + 3) = gcd(2(21n + 4), 3(14n + 3)) = gcd(42n + 8, 42n + 9) = gcd(42n + 8, 1) = 1 ∴ (21n + 4) / (14n + 3) is irreducible. QED View quoted note →
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